Students should have completed Lesson 1 Motion Builder 1D - Position and Velocity Graphs. They will require a working knowledge of the vector quantities position, displacement, and velocity. Students should also be familiar with basic graphing skills including slope and area calculations.
Students will be able to use graphical analysis to describe one-dimensional motion. Specifically, they will be able to generate and interpret position-time, velocity-time and acceleration-time graphs. Students will also be able to use slope and area calculations to generate data and solve problems.
Students should understand the applet functions that are described in Help and ShowMe. The applet should be open. The step-by-step instructions on this page are to be done in the applet. You may need to toggle back and forth between instructions and applet if your screen space is limited.
The space shuttle launch is an example of non-uniform (accelerated) motion. Graphical analysis of the shuttle's position with respect to time will reveal the relationships between position, velocity and acceleration. |
Use the 2D Uniform Motion Builder Graphing (pos, vel) applet to generate a position-time graph for the shuttle launch, which is initially at rest (v = 0.0 m/s) and accelerates at 5.0 m/s2 for 10.0 s.
On the applet, click "Reset" () and then "Add" () to add an object.
In the "EditorDialog" window enter a time of 10.0 s,
an initial velocity of 0.0 m/s and an acceleration of 5.0 m/s2.
Click "Play" () and observe the moving object () accelerate.
To view the position-time graph:
Click "Graph" ()
Set "x-axis" to "time"()
Set "y-axis" to "position" ()
Click "Fit Graph" ()
Verify that your graph is identical to Figure 1. The slope value is displayed under "output" and represents the shuttle's instantaneous velocity at the selected time. For example, Figure 1 shows an instantaneous velocity of +25.0 m/s at 5.0 s.
Figure 1: Position-Time
Explain how you can tell, by visual inspection, that the motion of the shuttle is not uniform, but is speeding up. In your explanation refer to the term slope. |
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Use the position-time graph created in Exercise 1 and the "Slope" tool () to complete the following tasks.
Velocity vs. Time |
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Which of the following best describes Graph 1: Velocity-Time? Write an equation expressing the relation between velocity and time.
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It is clear from the previous
exercises that the velocity of the shuttle discussed above is not constant. The velocity
is continuously changing from a value of 0.0 m/s to a value of 40.0 m/s after 8.0 seconds.
There is clear evidence that the shuttle is accelerating.
Use the applet to create a velocity-time graph based on the same time, velocity, and acceleration values that were entered in Exercise 1 by doing the following:
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Use the applet to create an acceleration-time graph based on the same time, velocity, and acceleration values that were entered in Exercise 1 by doing the following.
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Acceleration vs. Time
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In this section, we will explore the idea that area is a measure of the total or cumulative change in some variable. The variables will include position, velocity, and acceleration.
Fill in the blanks using the terms position, velocity, or acceleration.
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Use the applet to generate an acceleration-time graph for a ball falling from rest (v = 0.0 m/s) for 5.0 seconds.
Clear all objects from the applet by selecting them and clicking "Remove" ().
Click "Reset" () and then "Add" () to add an object.
In the "EditorDialog" window enter a time of 5.0 s, an initial velocity of 0.0 m/s and an acceleration of -9.81 m/s2.
Click "Play" () and observe the moving object () accelerate.
Generate an acceleration-time graph and click "Fit Graph" ().
Verify that your graph is identical to Figure 2: Acceleration-Time.
Figure 2: Acceleration-Time
Using the "Area" tool (), sweep out the area (from left to right) between t = 0.0 s and each of the following times. (Double-click on "Area" () to enter the exact time value for the point you wish to examine. The area should be green and will be displayed under "output".)
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Each of the areas that were measured are rectangles. The area of a rectangle is just "length x height".
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The results of Exercise 10 show that the area of an acceleration-time graph indicates the total change in the velocity of the motion. The same is true when relating velocity and position. | ||||||||||||||||||
Use the applet to create a velocity-time graph based on the same time, velocity, and acceleration values that were entered in Exercise 8 by doing the following.
Figure 3: Velocity-Time |
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Using the "Area" tool (), sweep out the area (from left to right) between t = 0.0 s and each of the following times. (Double-click on "Area" () to enter the exact time value for the point you wish to examine. The area should be green and will be displayed under "output".)
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Each of the areas that were measured are triangles. The area of a triangle is just 1/2 "length x height".
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Plot the data collected in Exercise 12. Explain what this graph shows. Why are all of the positions "negative"? Position vs. Time |
The slope and area properties of graphs are related to the actual properties of motion. This is summarized in the table below.
Slope Properties
Figure 4: Slope Summary
Area Properties
Figure 5: Area Summary
Consider some complex motion situations in which an object undergoes several different accelerations. Use 2D Uniform Motion Builder Graphing (pos, vel) to assist you in answering these questions.
You are riding in an elevator. Starting from rest, the elevator undergoes the following motions.
Complete the following graphs: Position vs. Time Velocity vs. Time Acceleration vs. Time
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Brenda is standing on the edge of a cliff and tosses her physics book upward with a speed of 22.0 m/s. It hits the ground at the base of the cliff 6.0 s later. Use 2D Uniform Motion Builder Graphing (pos, vel) to determine how high the cliff is and how fast the book was moving when it landed. |
You are programming a control computer for a subway train with the following parameters.
The train can accelerate from rest (v = 0.0 m/s) at 2.00 m/s2.
The maximum speed of the train is 30.0 m/s.
The train can brake at 3.00 m/s2.
The total distance that the subway car travels between stops is 1.0 km.
Use the following questions and the applet to help create motion scripts that could accomplish this.
How much time is required to accelerate from rest at 2.00 m/s2
in order to achieve the maximum speed?
How far does the subway train travel while accelerating up to the
maximum speed?
How long will it take the train to stop if it starts at the maximum
speed and accelerates at 3.00 m/s2?
How far does the subway train travel while stopping?
Given the starting and stopping distances (b and c), how far and how
long does the train travel at the maximum speed?
How much time will it take for the subway train to travel between the
stops?
What is the average speed of the train as it travels between stops?
Give the three motion scripts which will be used to control the
train:
time: ______ s , initial velocity ______ m/s, acceleration: ______ m/s2
time: ______ s , initial velocity ______ m/s, acceleration: ______ m/s2
time: ______ s , initial velocity ______ m/s, acceleration:
______ m/s2
Position vs. Time |
Velocity vs. Time |
Acceleration vs. Time |
Physics 20-30 v1.0
©2004 Alberta Learning (www.learnalberta.ca)
Last Updated: June 16, 2004